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Category: REASONIG
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As you know Reasoning is of high importance in getting a good score in Forthcoming Exams. Thus, we are sharing with you a practice set of Reasoning to help you prepare better for the upcoming exams. We hope this post will assist you in sharpening your reasoning skills. All the best folks.
Composite Time to complete this easy level set: 8 minutes
Reasoning Ability:
Directions (Q. 1-5): Given below is a passage followed by three questions. Answer the questions on the basis of the information given in the passage.
Puja, Neelu, Rajan, Sonia, Tanu and Manvi are six students of a school, one each studies in class I-VI. Each of them has a favourite colour from red, black, blue, yellow, pink and green, not necessarily in the same order.
Neelu likes black and does not study in class IV or V. The one who studies in Class IV does not like green. Puja studies in Class II. Manvi likes blue and does not study in Class IV. The one who likes yellow studies in class VI. Sonia likes pink and studies in Class I. Rajan does not study in Class VI.
Question.1. In which class does the person who likes red colour study?
1) V
2) III
3) IV
4) Data inadequate
5) None of these
Question.2. Which colour does Rajan like?
1) Black
2) Yellow
3) Green
4) Blue
5) None of these
Question.3. Which colour does Puja like?
1) Green
2) Yellow
3) Red
4) Data inadequate
5) None of these
Question.4. Which of the following combinations is correct?
1) Puja-II-Yellow
2) Neelu-III- Green
3) Sonia-I- Black
4) Tanu-V- Yellow
5) None of these
Question.5. In which class does Manvi study?
1) IV
2) III
3) II
4) V
5) None of these
Directions (Q. 6 to 10): Answer the questions on the basis of the information given below.
Nine people, P, Q, R, S, T, M, N, O and J stay in a building, but not necessarily in the same order. The building has nine floors and only one person stays on one floor. All of them own one car each, and each car is of a different colour, i.e. blue, grey, white, black, yellow, green, red, orange and pink, but not necessarily in the same order. The ground floor is numbered 1, the floor above it is numbered 2, and so on, and the topmost floor is numbered 9.
O owns a black-coloured car and stays on an evennumbered floor. P stays on any even-numbered floor below the floor on which O stays. The one who owns an orange- coloured car stays on the fourth floor. T stays on the second floor and owns a white-coloured car. The one who owns a pink-coloured car stays on the third floor. P does not own a green-coloured car. There are two floors between the floors on which the people owning the red and the black-coloured cars stay. R owns a grey-coloured car. There are three floors between the floors on which R and N stay. S stays on a floor immediately above J’s floor. There is one floor between the floors on which M and N stay. M does not own the pink- coloured car. The one who owns the blue car stays on the topmost floor. M does not stay on the ground floor.
Question.6. Who amongst the following owns the green coloured car?
1) S
2) J
3) N
4) M
5) None of these
Question.7. Who amongst the following stays on the topmost floor?
1) M
2) N
3) S
4) R
5) None of these
Question.8. P owns a car of which of the following colours?
1) Orange
2) Pink
3) Yellow
4) Blue
5) None of these
Question.9. Who stays on the floor which is exactly between the floor on which O stays and the floor on which P stays?
1) Q
2) N
3) R
4) M
5) None of these
Question.10. How many floors are there between the floor on which J stays and the floor on which R stays?
1) One
2) Two
3) None
4) Three
5) More than three
Solutions:
Answer.1. 3
Answer.2. 5
Answer.3. 1
Answer.4. 5
Answer.5. 4
Answer.6. 4
Answer.7. 5
Answer.8. 3
Answer.9. 4
Answer.10. 1
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When we are doing order and ranking we know basically two type of symbols first is greater than(>)and the other one is less than(<).To solve these questions we only know the three things:
Ordering and Ranking Arrangement is an important topic from the point of view of SBI PO, SBI Clerk, IBPS PO, IBPS Clerk, SSC, CAT and many other competitive exams. There are usually 3-5 questions in any exam from this topic. By following some simple shortcut tricks, you can easily crack the questions in a matter of seconds. This can be helpful in boosting your reasoning ability and, more importantly, your marks in the exam. Time is an important factor in qualifying through these competitive exams, and short tricks are the only way to go about getting through the Reasoning section with ease.
In ordering and ranking arrangement questions, position/rank of a person from left-right/top-bottom of a row/class is to be determined or rank/position is given & total no. of persons is to be calculated. You may also be asked to determine, using data given, which floor which person lives on.
Note:
1) Read the statement line by line and apply the cases as explained below.
2) Position can be from either sides of row and rank is always from top or bottom of the row
Here, different types of ordering & ranking arrangement questions are explained below with the help of different examples. By grasping each type, you can have a complete command over this topic and ensure 3-5 marks in your kitty.
TRICK 1
1) Total number of persons = {(sum of positions of same person from both sides i.e. left and right side) – 1}
OR
2) Position of a person from opposite side = {(Total no. of persons – Position of same person from given side) +1}
E.g.1) In a row of persons, position of A from left side of the row is 27^{th} and position of A from right side of the row is 34^{th}. Find total no. of persons in the row?
Solution:
Total no. of students = (Position of A from left + Position of A from right) -1
⇒Total no. of students = (27 + 34) – 1 = 61 – 1 = 60
E.g. 2) In a row of 16 persons, position of A from left side of the row is 12^{th}. Find the position of A from right side of the row?
Solution:
Position of A from right side = {(Total no. of persons – Position of A from left side) + 1}
⇒Position of A from right side = (16 – 12) + 1 = 4 + 1 = 5^{th}
1) Total no. of persons = No. of persons after or before the given person in a row + Position of same person from the other side
OR
2) No. of persons after or before the given person in a row = Total no. of persons – Position of same person from other side
E.g.1) In a row of persons, position of A from left side of the row is 27^{th} and there are 5 persons after A in the row. Find total no. of persons in the row?
Solution:
No. of persons in the row = Position of A from left + No. of persons after A
⇒ Total no. of persons = 27 + 5 = 32
E.g.2) In a row of 18 persons, position of A from left side of the row is 6^{th}. Find the no. of persons after A in the row?
Solution:
No. of persons after A = Total no. of persons – Position of A from left
⇒ No. of persons after A in the row = 18 – 6 = 12
TRICK 3
When the positions of two persons are given from opposite ends and we know the total number of persons, then two cases arise when trying to determine the number of persons between these two persons –
Case i)
No. of students between two different persons = Total no. of students – (Sum of positions of two different persons from opposite sides)
E.g.1) In a row of 54 persons, A is 15^{th} from the left side of the row and B is 20^{th} from the right side of the row. Find the no. of persons sitting between A and B?
Solution: Here Sum of positions of A & B from opposite ends = 15 + 20 = 35 < Total no. of persons
∴ No. of persons between A & B = Total no. of students – (Position of A from left + Position of B from right)
⇒ No. of persons between A & B = 54 – (15+20) = 54 – 35 = 19
Case ii)
No. of students between two different persons = (Sum of positions of two different persons from opposite sides) – Total no. of students – 2
E.g.1) In a row of 54 persons, A is 35^{th} from the left side of the row and B is 22^{nd} from the right side of the row. Find the no. of persons sitting between A and B?
Solution: Here Sum of positions of A & B from opposite ends = 35 + 22 = 57 > Total no. of persons
∴ No. of persons between A & B = (Position of A from left + Position of B from right) – Total no. of students – 2
⇒ No. of persons between A & B = (35+22) – 54 – 2 = 57 – 54 – 2 = 1
If total no. of students is to be calculated and positions of different persons from any side are given then it is always a case of ‘cannot be determined’ or ‘data inadequate’ or ‘can’t say’. This is because we do not know if there is overlapping or not.
E.g. In a row Position of A from left side of the row is 18^{th} and position of B from right side of the row is 25^{th}. Find the total no. of students in the row?
Solution: Cannot be determined as position of different persons is given from the same side.
TRICK 5
Positions of two persons is given and their positions are interchanged and after interchanging position of 1^{st} person is given from same side as before interchanging
E.g. A and B are standing in a row of persons. A is 18^{th} from left side of the row and B is 24^{th} from right side of the row. If they interchange their positions A becomes 31^{st} from left. Find
Solution:
⇒ New position of B from right side = 24 + (31 – 18) = 24 + 13 = 37^{th}
⇒ Total no. of persons = (B’s position from right after interchanging + A’s position from left before interchanging) – 1
⇒ Total no. of persons = (24 + 31) – 1 = 55 – 1 = 54
iii) No. of persons between A & B = (Position of A from left after interchanging– Position of A from left before interchanging) – 1
⇒ No. of persons between A & B = (31 – 18) – 1 = 13 – 1 = 12
If positions of two different persons are given from opposite sides of the row and a third person is sitting exactly in middle of the two and total no. of persons in the row is to be calculated as
Then find the position of the 3^{rd} person from both sides of the row and hence find total no. of persons according to type 1
E.g. 1) In a row of persons, position of A from left side of the row is 9^{th} & position of B from right side of the row is 8^{th}.If C is sitting just in middle of A & B and position of C from left side of the row is 15^{th}. Find the total no. of persons in the row?
Solution: Position of C from left is 15^{th} and A from left is 9^{th} so there are (15 – 9 – 1 = 5) persons are sitting between A and C. As C is sitting in middle of A and B so there must also be 5 persons sitting between B and C.
Thus position of C from right = Position of B from right + 5 + 1 = 8 + 6 = 14^{th}
Total no. of students = (Sum of positions of C from both sides – 1)
⇒ Total no. of students = (15 + 14) – 1 = 29 – 1 = 28
E.g. 2) In a row of persons, Position of A from left side of the row is 11^{th} and B from right side of the row is 19^{th}. If C is sitting just in middle of A & B and position of C from A is 7^{th}. Find total no. of persons in the row?
Solution: Position of C from Left = Position of A from left + Position of C from A = 11 + 7 = 18^{th}
Given C is 7^{th} from A and C is sitting in middle of A and B then also C is at 7^{th} position from B
Position of C from right = Position of B from right + Position of C from B = 19 + 7 = 26^{th}
Total no. of students = (Sum of position of C from both sides – 1)
⇒ Total no. of students = (18 + 26) – 1 = 44 – 1 = 43
TRICK 7
In the questions where it is asked to find minimum no. of persons in a row then it is always a case of overlapping i.e. given positions of persons from either sides overlap each other.
Then
Minimum no. of persons = Sum of positions of persons from both sides – Persons between them – 2
E.g. If position of A from left side of a row is 15^{th} and position of B from right side of a row is 19^{th} and only 1 person is sitting in middle of A & B. Find the minimum number of persons that can be seated in this row?
Solution: Total no. of persons = 15 + 19 – 1 – 2 = 31
Type 8
These are ordering type questions. In this type of question, it is given that there are several people living in an n-storey building. Some information will be given about the relative positions of one above or below the other. You need to find which floor each person lives on. These are almost similar to seating arrangement questions. However, you may be required to apply the rules you learnt above, in these problems.
left + left | Down |
Left + right | Up |
Right + left | Up |
Right + right | Down |
Up + left | Left |
Up + right | Right |
Down + left | Right |
Down + right | Lef |
Ques 1.
If exactly two swimming finish between J and L, then which of the following must be true?
(a) J finishes first
(b) o finishes first
(c) K finishes second
(d) M finishes fifth
(e) None of the above
Ques 2.
Which of the following cannot be true?
(a) K Finishes third
(b) K finishes sixth
(c) M finishes second
(d) N finishes fourth
(e) None of the above
Ques 3.
If N finishes directly ahead of K, then which of the following is a complete and accurate listing of the positions in which m could have finished?
(a) second
(b) Third
(c) Second, third
(d) Second, third , fourth
(e) None of the above’
Ques 4.
If O and K finish so that one is directly behind the other, Then which of the following must be true?
(a) K finishes sixth
(b) O finishes seventh
(c) J finishes first
(d) L finishes third, J finishes seventh
(e) None of the above
Ans 4. L finishes third , J Finishes seventh
Ques 5.
If J finishes first, and if L finishes ahead of N, then in How many different orders is it possible for the other swimmers to finish ?
(a) 2
(b) 3
(c) 4
(d) 5
(e) none of the above
Verbal reasoning has a very important chapter called– Directions. Direction sense test questions are not very tough to handle. The concept behind the directions is same that we use in our day to day life. We go to market, move left and right then up and down…we go far from our destination. Questions are asked in which direction we are right now from our home. This direction sense test is nothing but a precise of sensing the direction. To solve these types of questions you will need to make a sketch of the data provided in a rough paper. We will try to describe all tricks and tips regarding verbal reasoning’s direction sense test questions. Direction sense test questions are essential part of SSC, IBPS, Railway, CSAT or any other competitive exam covers at least 2-3 questions used to check the Imagination power and decision making caliber of any candidate.These are most easy question and should be solve within 2-3 second after reading the statement of question.
Rule 1: All LEFT turn will be taken ANTICLOCKWISE.
Rule 2: All RIGHT turn will be taken CLOCKWISE.
Note- At 12:00 noon is no shadow because the rays of the Sun are vertically downward.
Question: Himesh starts to walk towards east from his home and traveled 15 meters. He then takes a left turn and walked 10m. Again he takes a right turn and walked 07m finally he takes a right turn and walks 10m and takes his destination. So how far is he from his starting position and which direction is he facing?
And the options are:
Solution: For solving the question, you might take to draw a diagram on paper. For example consider 2cm as a 5m, You have to think that you are travelling the distance. The most important thing to care about is ‘in which direction the person starts’. So read the question very carefully first and then start as the given points of solution are below:
In the question above the person Himesh starts walking in east direction as given.
Answer: So Himesh is 15+07 = 22 meters far from his home and direction he is facing is east.
Option C
Explanation:
The movements of Rohit are shown in figure.
Rohit’s distance from the starting point A will be
AE = AD+DE = 20 + 15 = 35 metre
And direction with reference to the starting point is east.
Option A
Explanation:
Please refer to the explanation image.
The man firstly faces the direction OA. On moving 45 degree clockwise[Please check carefully always if clockwise or anticlockwise], he faces the direction OB.
Now again he moved 180 degree clockwise, now he will be facing OC. From here he moved 270 degree anticlockwise, Finally he is facing OD, which is South west.
Option B
Explanation:
Please check the movements of Lokesh in the figure.
Finally he is to the North to his house.
Option D
Explanation:
Clearly, Kunal moves from A 10 Km northwards upto B, then moves 6 Km southwards upto C, turns towards east and moves 3 km upto D.
Then AC = (AB-BC) = 4 Km
So Kunal distance from starting point A
\begin{aligned}
AD = \sqrt{AC^2 + CD^2} \\
= \sqrt{4^2+3^2} \\
= \sqrt{25} = 5
\end{aligned}
So AD is 5 Km also with reference to starting point Kunal’s direction is North-East.
Option B
Explanation:
Now dog is facing North.
Option D
Explanation:
Please refer to the explanation image.
The man firstly faces the direction OA. On moving 45 degree clockwise, he faces the direction OB.
Now again he moved 180 degree clockwise, now he will be facing OC. From here he moved 45 degree anticlockwise, Finally he is facing OD, which is South direction.
Option E
Explanation:
Please check the movements of Gaurav in the figure.
Now, Gaurav distance from his initial position A to E
AE = (AD+DE) = 40 + 20 = 60 metres
Hope this helpful for you to clear the concept direction based questions. Please send your feedback and suggestion on comment section below and all. Best wishes for your exam.
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